I did, it seems to work

That's strange, because for me it didn't work: 

use threads;
use threads::shared;

my %sa : shared = ();
%{$sa{foo}} = ();
__END__
Invalid value for shared scalar at share_share.pl line 5.

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In reply to Re^5: Shared hash within shared hash of hash??? by zwon
in thread Shared hash within shared hash of hash??? by ISAI student

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