Let me try to be more clear on what I mean:

in the following arrays qw/name pos loc age/ and qw/car dog age/ the "age" field is present in the first array already, so I don't want to add it again, I want to add the in the "age" (=last) position in the second array to the already existing "age" position in the final combined arref..

I hope that explains it a bit.

I can post the code I built up which doesn't look nice, though it does the job.. I'd prefer to have something nicer if possible

my $arr = [[qw/name pos loc age/],
       [qw/ike boss 12 44/],
       [qw/mat slave 22 21/],
       [qw/jill sec 15 32/],];

my $add = [[qw/car dog age/],
       [qw/a1 grr 3/],
       [qw/s2 miew 7/],];

my ($arrfld,$addfld);
for ($i=0;$i<@{$arr->[0]};$i++){ $arrfld->{ $arr->[0]->[$i] } = $i }
for ($i=0;$i<@{$add->[0]};$i++){
  unless ( $arrfld->{ $add->[0]->[$i] } ){ 
    $arrfld->{ $add->[0]->[$i] } = scalar(keys %$arrfld);
  }
  $addfld->{ $arrfld->{ $add->[0]->[$i] } } = $i;
}
foreach my $row (@$arr){
  for($x=scalar(@$row);$x<scalar(keys %$arrfld);$x++){push @$row,""}
}
shift @$add;
foreach my $row (@$add){
  my $nr;
  for ($x=0;$x<scalar(keys %$arrfld);$x++){
    $nr->[$x] = defined($addfld->{$x})?$row->[$addfld->{$x}]:""; 
  }
  push @$arr,$nr;
}

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In reply to Re: Merging two array(refs) by kpiti
in thread Merging two array(refs) by kpiti

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