$var[$j] =~ s/\.\.\./\.\+/g;

The right half of an s/// substitution is not a regex, but a mere string. So if you want to construct .+ in the replacement, you need to write it as .+ and not at \.\+.

Perl 6 - the future is here, just unevenly distributed

In reply to Re: Using special characters in left part of a regex match? by moritz
in thread Using special characters in left part of a regex match? by shamat

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