Well, seems this example makes more sense. 
my $a = 0;
my $b = 2;
my $z = \($a && $b);
$$z = 4;
print $a;

[download]
(prints 4)

In reply to Re: Why Perl boolean expression sometimes treated as lvalue? by vsespb
in thread Why Perl boolean expression sometimes treated as lvalue? by vsespb

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