perlop perlop perlop , precedence is everything :) 

$ perl -E " print ( 1 && 2 )
2

$ perl -E " sub ff { ++$_[0] } my($f,$a)=(1,5); ff( $f && $a ); say $f
+; say $a; "
1
6

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In reply to Re^2: Why Perl boolean expression sometimes treated as lvalue? (perlop, precedence) by Anonymous Monk
in thread Why Perl boolean expression sometimes treated as lvalue? by vsespb

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