Hmmm... interesting disparity. The following may be of interest...
use v5.10; my ($a, $b) = (0, 0); sub lv :lvalue { $_[0] } lv($a || $b) = 2; lv($a && $b) = 1; say $a; say $b;
In reply to Re: Why Perl boolean expression sometimes treated as lvalue?
by tobyink
in thread Why Perl boolean expression sometimes treated as lvalue?
by vsespb
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |