The transform 3-$l only works if you are working with 1 and 2 as your permuted set; it happens that for that set 3-$l is equivalent to "the member of the set that is not $l". If you need any degree of flexibility, you should follow the code in Re: How can one generate all possible combinations with reference to string positions?, subject to BrowserUK's comments.

#11929 First ask yourself `How would I do this without a computer?' Then have the computer do it the same way.

In reply to Re^3: How can one generate all possible combinations with reference to string positions? by kennethk
in thread How can one generate all possible combinations with reference to string positions? by supriyoch_2008

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