Here's a solution that does what you're after. The substitution is: 

s{\[\[(.*?)\]\]}{$1 =~ s/ /_/gr}e

[download]

I've added an additional test to check that various embedded brackets do not cause issues. 

$ perl -Mstrict -Mwarnings -E '
my $x = q{Here are [[a variable number of words]] in brackets};
say $x;
$x =~ s{\[\[(.*?)\]\]}{$1 =~ s/ /_/gr}e;
say $x;
my $y = q{Here are [[a variab]le number [ of ] wo[rds]] in brackets};
say $y;
$y =~ s{\[\[(.*?)\]\]}{$1 =~ s/ /_/gr}e;
say $y;
'
Here are [[a variable number of words]] in brackets
Here are a_variable_number_of_words in brackets
Here are [[a variab]le number [ of ] wo[rds]] in brackets
Here are a_variab]le_number_[_of_]_wo[rds in brackets

[download]

-- Ken

In reply to Re: substitute characters in the RHS of a search & replace by kcott
in thread substitute characters in the RHS of a search & replace by Anonymous Monk

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