something like:
2^3 for negative
2^2 for special value
2^4 for infinity
couldn't find explanation in the docs.
> decided they all looked somewhat flakey,
agreed, but shouldn't we try to fix it.
Don't you think the algorithm I used is a valid use case? (non-reachable integer)
Cheers Rolf
( addicted to the Perl Programming Language)
In reply to Re^4: Incrementing "Infinity" bug
by LanX
in thread Incrementing "Infinity" bug
by LanX
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