Sounds like you've got a very straightforward algorithm laid out there. It is difficult to be both "greater" and "equal" at the same time, but I presume you meant to say "or".

You may have also noticed how repetitive it is, and that it can be reworded as a for loop, using N, and (N+1)%$numTidePoints

In reply to Re^5: Display tide based on time now. by Anonymous Monk
in thread Display tide based on time now. by Anonymous Monk

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