Dear Monks,

I have a quite complicated object (for various reason it has to be like this) and by using this example I want to ask how to do to specific tasks. I hope it will be easy to understand.

#Created by using; push @{ $Second{Company}->{Identifier} }, Element;

%Hash   -> {Company_A} -> { Identifier_1 } -> One or more 'Elements' e
+xample (a, b) 
                       -> { Identifier_2 } -> One or more 'Elements' e
+xample (b, g)                              
                       -> { Identifier_3 } -> One or more 'Elements' e
+xample (c) 

        -> {Company_B} -> { Identifier_1 } -> One or more 'Elements' e
+xample (a) 
                       -> { Identifier_2 } -> One or more 'Elements' e
+xample (g) 
                       -> { Identifier_3 } -> One or more 'Elements' e
+xample (x)

[download]

1) I want to know how many 'b' elements is there in Company_A. Usually I would use something like map { $Count+= 1 if 'a' eq values %Hash{Company_A}{$_} } values %Hash{Company_A}; but it will only access the first element of each Identifier. How can I write a map command to go through every element?

2) When I need to print this hash I have to look if each identifier has one or more elements (scalar) and fork the prints to print out everything in line by line case (foreach and use count++). Amount of elements vary and there is a lot of data inside so I don't want to create duplicate entries</pp> 

scalar ()

if more than 1 {
    foreach
    $Company_A{Identifier_1}[$Count]
    $Company_A{Identifier_2}[$Count]
    $Company_A{Identifier_3}
    $Count++
}
if = 1 {
    $Company_B{Identifier_1}
    $Company_B{Identifier_2}
    $Company_B{Identifier_3}
}

Ouptut:

Company_A a, b, c
Company_A b, g, c
Company_B a, g, x

[download]

Some Identifiers have more elements (always equal amount) and other have only one. I need to print the ones with multiple elements separately - they share the elements which only appear once. Because I am doing it for separate objects I was wondering if there is a way to print everything in one block with a single command?

Thanks so much for any tips. Humble apprentice

In reply to Searching and printing complex data structures by Anonymous Monk

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