> I can see what it's doing, but don't understand how the bind in $0 =~ m!/?([^/]+$)! strips the path off - or, in fact, returns anything.

In list context the match returns a list of those (grouped) submatches.

In this case everything "non /" [^/] between one or none slash /? and end of string $.

HTH =)

Cheers Rolf

( addicted to the Perl Programming Language)

EDIT: I'm not sure if it makes sense to put $ is within the group. Not my style...

UPDATE

CAREFUL!!!

This Basename() routine is dangerous cause it expects a scalar to be returned but only in list context!

  DB<116> $0="a/b"
 => "a/b"

  DB<117> @a=Basename()  
 => "b"                     # all grouped matches

  DB<118> $a=Basename()
 => 1                       # true it matched

[download]

Plz be aware that the context is propageted to return.

UPDATE

thx Athanasius for spotting the same problem... race condition between my update and your post :)

In reply to Re: Return value from a binding operator? by LanX
in thread Return value from a binding operator? by Spinone

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