Non-Perl answer:

head -1 *files | grep "#!" > shebang.txt Obviously a unix/linux answer.

Scott

Do'h! Before anyone else writes, this won't exactly work, since you'll only get the #! line, but not the file it came from. Gimme a second...

Update 2: OK, you didn't ask for the file it came from, so it is a workable solution. If you want the file as well, do the head, do something like this: 

@temp = `head -1 *files`;

for ($i=0;$i<scalar @temp;$i++) {
   if ($temp[$i] =~ /^#!/) {              #fixed a typo
      print "$temp[$1-1], $temp[$i]\n";
   }
}

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In reply to Re: Quickly reading the first line of a large number of files... by scain
in thread Quickly reading the first line of a large number of files... by Snowman

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