> "sub foo {}" doesn't count as a run-time statment.

Ah I see! Now this explains why wrapping with do {... } helps.

> $ say '$^D=$^D; (); sub foo {}'

Good idea! I'll do that, thanks!

Cheers Rolf

( addicted to the Perl Programming Language)

In reply to Re^2: Hacking Debugger bugs connected to $^D (()) by LanX
in thread Hacking Debugger bugs connected to $^D by LanX

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