Yes, I'm aware of that. That's why this is post is in Obfuscated Code rather than Meditations. If you want to get the real solution, the simpler
prints it together with another fake solution.use 5.012; no warnings; my @t = map { rand } 1..60; my %g = (k => \@t) +; for my $n (0..1e3) { (my $s = $n) =~ y/0-9/ {}@#$%=^~+/; my $c= qq( +${s}g{k}}); if (60 == eval $c) { warn $c; } }
In reply to Re^2: Length of array in hash of arrays
by ambrus
in thread Length of array in hash of arrays
by ambrus
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