Hi. I am writing a program where i sometimes have to redirect STDOUT. When i want to restore it I use the following code

open ($oldout,'>&',\*STDOUT);

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I found this on the internet and it works fine, but i don't know what '>&' means exactly. I've been going through my documentation but i can't find anything. Can someone explain why the & sign needs to be there? ty.

In reply to rerouting STDOUT by Anonymous Monk

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