Thank you rjt. Now it's clear to me how "v" flag works. The documentation for this flag is so obscure and it needs to be clarified.

I have seen some code as:

printf "%vd","\x5\xE\x2"; # print 5.14.2

[download]

how does perl interpret "\" here? It seems it considers it as escape for "x" instead of a single character.

but why put "\x" before each of these characters ("5", "E", "2")?

Thank you very much.

In reply to Re^2: question regarding "v" flag of printf by lightoverhead
in thread question regarding "v" flag of printf by lightoverhead

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