In your example, $aa would get the value of $a, and @bb would get ($b, $c). I don't know what you mean by "elements of @bb, but sorted individually", because $a isn't a member of @bb.

Could you describe what you're trying to do a little better?

In reply to Re: i don't know rather take a look below by bikeNomad
in thread i don't know rather take a look below by nehlwyn

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