Since you do not declare your hash inside of your for loop, it is always the same one you push into the array. You do not have a new one with new values, you just replace them.

There are two things you can do. Either declare your hash lexically (with my) inside the for loop, and you'll have a brand new one each time, or youcan make a new one to push into AOH. With push @AOH, { %hash }; # copy of %hash here

Both are possible, but it would probably be better to have your my %hash in the for loop, because you can be sure to have only new values, not ones that you somehow didn't delete or change.

In reply to Re: building array of hashes by Eily
in thread building array of hashes by fionbarr

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