> I don't understand the point about real efficiency,

Maybe an example helps illustrating the point.

What is more efficient:

 for (1..1e6) { ... }

or

 @k=1..1e6; for (@k) {...} ?

> but if you want absolutely no dependencies,

I definitely need no dependency b/c this lazy iterator breaks if comparing identical hashes.

This seems like a trivially avoided case but, what if you working with deeply nested data-structures?

This effectively means:

NEVER use each within an iterator operating on a shared data structure, cause it has global side effects!

> you can always roll your own iterator.

I'm well aware, thats why asked how to avoid this.

Cheers Rolf

( addicted to the Perl Programming Language)


In reply to Re^4: Indepedent lazy iterators for the same hash? by LanX
in thread Indepedent lazy iterators for the same hash? by LanX

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