Looks to me like the second example is wrong. First,
understand that the first example really is a shortcut
for
my $myarray = shift @_;
Once you see
that, it makes sense that $myarray contains the first
element in @_ (which is the first argument passed to the
subroutine).
So, the second example would assign a '1' to $myarray,
because when you assign an array to a scalar, you get
the number of the elements of the array.
Here is a test script for you to play with:
use strict;
use Data::Dumper;
sub foo {
my $ref = shift;
print Dumper $ref;
}
sub bar {
my $ref = @_;
print Dumper $ref;
}
my @ary = qw(a b c d e f);
my $ref = [ qw(a b c d e f) ];
foo(@ary);
foo($ref);
bar(@ary);
bar($ref);
----------------------------------------------------
perl -le '$x="jeff";$x++ for(0..4482550);print $x'
----------------------------------------------------
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