Hi Alexander,

Perl is not C.

Let's look at a common idiom in Perl:

while(my $line = <>) {
   do_something($line);
}

[download]

This is an assignment in a conditional operator. It does fortunately not emit a warning. Let's look at a more or less equivalent code in C:

#include <stdio.h>
#include <stdlib.h>

int get_val(void);

int main(void) {
    int i, x, y;
    i = x = y = 0;
    while (x = get_val()) {
        i++;
        printf("in loop\n");
        if(i == 1) {
            exit(1);
        }
    }
    return i;
}

int get_val(void) {
    return(1);
}

[download]

Compiled with LANG=C gcc -Wall -pedantic -o warning warning.c it does emit the following:

warning.c: In function 'main':
warning.c:11: warning: suggest parentheses around assignment used as t
+ruth value

[download]

IMHO, it proves: Perl is not C, C is not Perl. C is a compiled language. Perl is a interpreted language.

In my opinion, the above Perl idiom should not emit a warning like C does.

Best regards
McA

P.S.: A ++ for your comparison.

In reply to Re^3: No warning when assiging to a variable by McA
in thread No warning when assiging to a variable by mikeraz

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