2. because thats how a variable is compared in regex
No, the variable $constant will be interpolated into the regex without the parentheses (round brackets). Consider:
1:31 >perl -wE "my $constant = 'fred'; my $string = 'fredflintstone'; + print qq[found $1\n] if $string =~ /^$constant/;" Use of uninitialized value $1 in concatenation (.) or string at -e lin +e 1. found 1:32 >perl -wE "my $constant = 'fred'; my $string = 'fredflintstone'; + print qq[found $1\n] if $string =~ /^($constant)/;" found fred 1:32 >
If the regex matches, any parentheses capture their contents into the special variables $1, $2, etc. But this incurs a performance penalty:
WARNING: Once Perl sees that you need one of $&, $`, or $' anywhere in the program, it has to provide them for every pattern match. This may substantially slow your program. Perl uses the same mechanism to produce $1, $2, etc, so you also pay a price for each pattern that contains capturing parentheses. (“Capture groups” in perlre#Regular-Expressions)
Since you’re not using $1, the capturing parentheses aren’t needed.
Hope that helps,
| Athanasius <°(((>< contra mundum | Iustus alius egestas vitae, eros Piratica, |
In reply to Re^3: Issue with regex matching
by Athanasius
in thread Issue with regex matching
by sowais
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |