Random_Walk has given a good explanation.
However, maybe the following line could help clear the that line a bit.
print $1,$/ if m{\s+?(\d+?)\/total$};
The above line shows clearly that after "total", what you have is "$" that indicate the end of the string and not "$/". The / that follows "$" is the second "slash" of the match operator i.e

m// ^ This one
In addition to all that, using the module "YAPE::Regex::Explain" the regular expression matches could be explain as thus:
The regular expression: (?-imsx:\s+?(\d+?)/total$) matches as follows: NODE EXPLANATION ---------------------------------------------------------------------- (?-imsx: group, but do not capture (case-sensitive) (with ^ and $ matching normally) (with . not matching \n) (matching whitespace and # normally): ---------------------------------------------------------------------- \s+? whitespace (\n, \r, \t, \f, and " ") (1 or more times (matching the least amount possible)) ---------------------------------------------------------------------- ( group and capture to \1: ---------------------------------------------------------------------- \d+? digits (0-9) (1 or more times (matching the least amount possible)) ---------------------------------------------------------------------- ) end of \1 ---------------------------------------------------------------------- /total '/total' ---------------------------------------------------------------------- $ before an optional \n, and the end of the string ---------------------------------------------------------------------- ) end of grouping ----------------------------------------------------------------------

If you tell me, I'll forget.
If you show me, I'll remember.
if you involve me, I'll understand.
--- Author unknown to me

In reply to Re^3: extract the value before a particualr string by 2teez
in thread extract the value before a particualr string by nanban

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