DB<100> %hash = (
                key1 => 10,
                key2 => 10,
                key3 => 3,
                key4 => 5,
                key5 => 10
           );
 => ("key1", 10, "key2", 10, "key3", 3, "key4", 5, "key5", 10)

  DB<101> $count{$_}++ for values %hash 
 => ""

  DB<102> \%count
 => { 3 => 1, 5 => 1, 10 => 3 }

  DB<106> ($max) = reverse sort values %count
 => 3

  DB<109> grep { $count{$_} == $max } %count
 => 10

[download]

this will give you a list of all values which are maximal, not only one.

update

otherwise, if only one value is enough:

  DB<119> %rcount= reverse %count
 => (3, 10, 3, 10)

  DB<120> \%rcount 
 => { 1 => 3, 3 => 10 }

  DB<121> $rcount{$max}
 => 10

[download]

and here an easier approach to find the maxmimum.

  DB<113> use List::Util qw/max/

  DB<114> $max = max values  %count
 => 3

[download]

Cheers Rolf

( addicted to the Perl Programming Language)

In reply to Re: How to compare hash values within the same hash? by LanX
in thread How to compare hash values within the same hash? by phildeman

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