Yeah I agree about 12_461_993

Anyway you don't need to check against all words in the dictionary, only taking the (at most) 256 subsets of a potential 8 letter combination. (less if letters are repeated)

This can be done in a lookup in a prepared count-hash with normalized keys.

Cheers Rolf

( addicted to the Perl Programming Language)

In reply to Re^7: Challenge: 8 Letters, Most Words by LanX
in thread Challenge: 8 Letters, Most Words by Limbic~Region

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