next if $bh_start < time; # history
If the program ist started on a holiday (even 1 second past midnight), the routine will think it is a workday... I wanted to propose
    ...
    use integer;
    my $today = time / 86400 * 86400; # chop hours, minutes, seconds
    while (<DATA>) { # read bank holiday file
        ...
        next if $bh_start < $today; # history
        ...
    }
    ...

[download]
but this doesn't work correctly, either, because time is in seconds since some 1970-01-01 UTC...

In reply to Re: efficient determination of in/out of hours by soonix
in thread efficient determination of in/out of hours including Bank Holidays by Random_Walk

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