Good evening Monks,
I have a very low level in Perl and I am trying to do something like:
$i=0;
print 'first=' , $i, ', ' if ($i++);
print 'middle=', $i, ', ' if ($i++);
print 'last=' , $i, ', ' if ($i++);
print 'beyond=', $i if $i++;
I was expecting something like (as '++' is AFTER the variable):
middle=1, last=2, beyond=3
While, instead, I get:
middle=2, last=3, beyond=4
I changed my code (first line only) to be:
print 'first=' , $i, ', ' if (++$i);
and I get:
first=1, middle=2, last=3, beyond=4
which only adds to my confusion.
Can someone help me and tell me why the
$var++ and the
++$var syntaxes do not produce what I was thinking right according to what (I understand to be) are the rules for the ++Var and Var++ syntaxes ? Meaning:
a) null 1 2 3
b) 1 1 2 3
TIA
Gilles
PS: I'm using activeState perl 5.014 under W7/64
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