I'm sure this is very simply, but my perl is very weak so I'm not really having much luck.

I have a string like such:

cd / ; /path/to/R/R_latest --vanilla --args "fName='rGSDPlan';jobCode= +682718;jobId=6827181;" < job682718.R > job_6827181.txt

I want to translate all ; to && except where they fall between double quotes. I'm sure this is pretty simple, but I'm having no luck. I need to do this within a bash shell script so I was looking to do a in place replace on the string.

Any tips would be appreciated!

In reply to In place replace, ignoring between quotes by Klainn

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