Hmm,

Altho' perfectly correct, methinx that the simple for loop construct you use is more normally written as 

push @ret, $coderef->() for @params;

[download]

In fact, simpler still would be use the incoming arg list directly and to use parens for the non-core call to foo (as per PBP) ... 

#!/usr/bin/env perl
use 5.010;
use strict;
use warnings;

sub foo(&@) {
    my $coderef = shift;
    my @ret;

    push @ret, $coderef->() for @_;

    return @ret;
}

my @a = ( "1", "2", "3", "4", );
my @b = foo( sub { $_ ** 2 }, @a);

[download]
Yet another product of an idle moment ...

A user level that continues to overstate my experience :-))

In reply to Re: [Solved] How does map work? by Bloodnok
in thread [Solved] How does map work? by three18ti

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