my $s = "foo bar quux";
my $pattern = q(foo (.*?) quux);
my $rep = q(foo quux $1);
$s =~ s|$pattern|$rep}|;
print "$s\n";
I would like for this to print 
foo quux bar
But instead I get 
foo quux $1
How can I get the substitution operator to expand the $1 embedded in the replacement variable?

In reply to Back substitution expansion by Anonymous Monk

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