Thx!²
But
> Consider the relative difficulty of fixing your problem case vs. my counter-factual problem case:
while( $x = shift @a ) { # Fixed
this is not a fix because while stops, if any element of @a is false.
DB<187> @a=(1,undef,2,3,0,4,5)
DB<188> print $x while $x =shift @a
1
DB<189> print $x while $x =shift @a
23
DB<190> print $x while $x =shift @a
45
DB<191> print $x while $x =shift @a
Thats the old semipredicate problem, which can only be solved with list-assignments.¹
But I agree with you that it's most probably too late to fix that design decision...
Cheers Rolf
( addicted to the Perl Programming Language)
¹) for completeness: no defined doesn't help here, if undef is a legal value.
updates
- corrected "semipredicate problem"
- improved code example
- your "better" update is indeed better
²) best answer so far
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