G'day tosaiju,

$2 is probably being modified somewhere between the two calls to function().

You've posted If instead of if. This should generate a syntax error. Instead of typing your code by hand when posting, copy and paste it: less effort; more accurate! It also means we're seeing your real code.

Also, do you need the leading &s? See perlsub.

Without seeing more of your code, I'd suggest something along these lines (untested): 

if ($str =~ m/(pattern1)(pattern2)/gi) {
    my ($arg1, $arg2) = ($1, $2);
    $str = function($arg1);
    $var1 = function($arg2);
}

[download]

-- Ken

In reply to Re: Regex, Function and Default variables by kcott
in thread Regex, Function and Default variables by tosaiju

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