I have been using some of this syntax. I was trying to also output a unique count of the numbers in the 3rd & 4th columns. I was trying to push the value's in the column onto an array, if it already is not already in the array. I think this is currently a scalar value but i would need an array/list. This is the error that I receive: Not an ARRAY reference at ./test.pl line 21, <DATA> line 1. I am thinking once I have the values in an array or list I can just print the list in scalar context to get the unique count? I don't know if there is a simpler way to achieve this.
#!/usr/bin/perl
use strict;
use warnings;
my $basecol=shift @ARGV or die "What base col?";
my %h;
$basecol--; # zero based inside program.
while (<DATA>){
chomp;
my @f= split ;
next unless @f > 1;
splice @f,0,0,$f[0] . "_". $f[1];
my $k = $f[$basecol];
$h{$k}{COUNT}++;
for my $col(0..$#f){
next if $col==$basecol;
$f[$col]=0 unless $f[$col]=~/^\d+$/;
$h{$k}{FIELD_S}[$col]+= $f[$col];
push($h{$k}{FIELD_C}[$col],$f[$col]) if !($f[$col] ~~ $h{$k}{FIELD
+_C}[$col]);
}
}
for (sort keys %h){
print "$_\t $h{$_}{COUNT}\t";
for my $f(@{ $h{$_}{FIELD_S} }){
defined $f or $f='';
print "$f\t";
}
print "\n";
}
__DATA__
U1 ID1 100 280
U1 ID1 137 250
U2 ID2 150 375
U1 ID2 100 100
U3 ID1 100 600
U9 ID3 137 200
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