Perl treats literals coded into your program with a leading 0 specially. 

perl -e '$a=017; $b=0x17; print "$a $b\n";'
15 23

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The first number which is treated as octal is 15 in decimal and the second is treated as hexidecimal and so is 23 decimal.

In reply to Re: perl -e0octal by dga
in thread perl -e0octal by Anonymous Monk

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