STDIN is okay. But do you think this program will work? Did

you run this program and check? Still there are very basic syntax errors in your program and this program will not work. You could have found out if you have executed this code

coding for print 47 
#!/usr/bin/perl

 
use strict;
use warnings;
 
print "Enter a number:";
my $input = <STDIN>;
chomp $input;
 
if ( $input == 47 );
   print "number is 47\n" 
else
   print " number does'not match . enter number again"

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In reply to have synax error in this coding? by virudinesh

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