DB<132> sub cycle { $_[1]++; $_[1] %= $_[0] } DB<133> cycle 3 => $h{a}{b}[2]{c}; \%h => { a => { b => [undef, undef, { c => 1 }] } } DB<134> cycle 3 => $h{a}{b}[2]{c}; \%h => { a => { b => [undef, undef, { c => 2 }] } } DB<135> cycle 3 => $h{a}{b}[2]{c}; \%h => { a => { b => [undef, undef, { c => 0 }] } }
unfortunately does Perl have no autoboxing, to allow:
$h{a}{b}[2]{c}->cycle(3)
Ha, it can be emulated with ano-subs! =)
DB<160> $cycle = sub { $_[0]++; $_[0] %= $_[1] } => sub { "???" } DB<161> $h{a}{b}[2]{c}->$cycle(3); \%h => { a => { b => [undef, undef, { c => 1 }] } } DB<162> $h{a}{b}[2]{c}->$cycle(3); \%h => { a => { b => [undef, undef, { c => 2 }] } } DB<163> $h{a}{b}[2]{c}->$cycle(3); \%h => { a => { b => [undef, undef, { c => 0 }] } }
Cheers Rolf
( addicted to the Perl Programming Language)
In reply to Re^2: A better (ie.more concise) way to write this?
by LanX
in thread A better (ie.more concise) way to write this?
by BrowserUk
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