Step through your first loop by hand and see what is assigned each time through it. $broken->{this} is assigned "1" the first time, but is being assigned "0" and the second and third pass. Similarly for $broken->{that} and $broken->{another}.

The end result is that only the results for the last pass is stored in the hash keys.

It helps to remember that the primary goal is to drain the swamp even when you are hip-deep in alligators.

In reply to Re: Ternary operators by boftx
in thread Ternary operators by geistberg

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