If subset size were known, you'd be counting the combinations. 

for my $n (100) {
  for my $m (1..100) {
    my $i = 1;
    $i *= ($n+1-$_)/$_ for 1..$m;
    printf "C($m,$n) = $i (%.3f bits)\n", log($i)/log(2);
  }
}

[download]
Sadly, representing even three elements requires > 16 bits.

In reply to Re: coding question by oiskuu
in thread coding question by baxy77bax

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