please use <code> tags!
Tried this: 
my $j = 1;
my $p = $s[1]; #values are present starting from 1st index
while ($j != $n - 1) {
    if ( ($p < $s[$j+1]) || ($p == $s[$j+1]) ) {
    }else{
        $p = $s[$j+1];    
    }
    $j++;
}

[download]
i guess that $p should keep the minimum value of the array, but the question is how to get its index.

well this code is broken in too many ways...

But to keep it short, you have to set a variable $min_idx=$j+1 in the else track.

Let me propose something more perlish

use strict;
use warnings;
use Data::Dump;


my @s= map { int rand 100 } 1..10;
dd \@s;

my $min_idx = 0;
my $idx     = 0;
my $min     = $s[0];

for my $value (@s) {
  ($min,$min_idx)=($value,$idx) if $value < $min ;
  $idx++;
}

dd $min,$min_idx;

[download]

out: 

[96, 40, 65, 98, 46, 17, 2, 60, 12, 67]
(2, 6)

[download]

Cheers Rolf

( addicted to the Perl Programming Language)

In reply to Re^5: index of the minimum element of the array by LanX
in thread index of the minimum element of the array by Anonymous Monk

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