The condition of the if is performed first: $x is false, so it needs the Right hand side of the OR. That prints 0, returns true, and then the if is satisfied (false or true => true). Then it prints 1 because the if said so.

This implies that the or applies to the condition after the if, not to the statement including the if:

print 1 if ($x || print 0)

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—John

In reply to Re: Weird syntax question by John M. Dlugosz
in thread Weird syntax question by Ovid

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