Through a little poking around, this evaluates as.. 
perl -e '$x=1;print 1 if ($x or print 0)'

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Which evalutates  ($x or print 0) first. That will always return true so the 1 gets printed in either case.

With the subs, it will evaluate to false since you're returning 0.

Rich

In reply to Re: Weird syntax question by rchiav
in thread Weird syntax question by Ovid

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