Include the reason of error by use of $! variable ... 

  open ... or die "Death is here because: $!.";

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Mind that readdir gives a file name below the directory being read from (relative path). You may need to supply the parent directory as appropriate to form correct path of file to be (found &) opened.

In reply to Re: cant open files from a directory by parv
in thread cant open files from a directory by garny

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