Based on perlop , the terany operator (?:) is just one precidence level above the "operate and set" operators .=, +=, etc.

Thus, perl is seeing: 

print ($x ? $x.="hello" : $x.="Bye");

[download]
as 
print (  ( $x ? $x.="hello" : $x ) .="Bye");

[download]
and not as 
print ( $x ? $x.="hello" : ( $x.="Bye" ) );

[download]
The solution is, therefore, to use the last form to get it the way you want.

-----------------------------------------------------
Dr. Michael K. Neylon - mneylon-pm@masemware.com || "You've left the lens cap of your mind on again, Pinky" - The Brain
It's not what you know, but knowing how to find it if you don't know that's important

In reply to Re: ?: (conditional operator) by Masem
in thread ?: (conditional operator) by pmc2

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