Thank you BrowserUK. You are right. It's good to learn.

what about this:

 for(;;){
     print "3:\t$ARGV[0]\n"; #cannot print either
       last;
   }

[download]
Is $ARGV[0] consumed too?

In reply to Re^2: @ARGV in while loop by lightoverhead
in thread @ARGV in while loop by lightoverhead

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