Edit: ikegami is right, I mistook precedence for evaluation order, and just kept being blinded by that mistake. Please read his correct explanation.

If you look at the precedence list in perlop, += is of higher precedence than ,, so it will be run first, just like the multiplication will be run before the addition in $c+$c*$_

In $c+0, $c+=1; + is the highest precedence operation, so addition is indeed run first. In $tmp = $c, $c+=1; = and += are of equivalent precedences, and so are run from left to right (and that's because of the , in between).

Edit: added a ; here and a ; there, because their absence made my post look confusing.

In reply to Re: Why does the first $c evaluate to the incremented value in [$c, $c += $_] ? by Eily
in thread Why does the first $c evaluate to the incremented value in [$c, $c += $_] ? by smls

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