In C, a comma operator is a "sequence point", meaning a statement such as y = (++x, ++x, ++x); is perfectly valid. (But (++x + ++x); is undefined behavior.) Comma in declaration list, initializers, parameter list, ..., is not an operator but a punctuator.

perlop says a comma in list context is "just the list argument separator". This is not a case with operator precedence. Indeed, it's a nasty bug!

perl -le '$c = 0; print @$_ for map { [$c, $c += $_] } (2,6,5,7);'
perl -le '$c = 0; print @$_ for map { ["$c", $c += $_] } (2,6,5,7);'

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In reply to Re: Why does the first $c evaluate to the incremented value ... (bug) by oiskuu
in thread Why does the first $c evaluate to the incremented value in [$c, $c += $_] ? by smls

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