Yep, this is what I get on Cygwin: 
$ perl -e '$x = (2**1025) / (2**1025);print $x;'
nan

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But, of course, I am not claiming this to prove my original assumption in any way. We are talking here about manipulating numbers many many orders of magnitude larger, nothing to do with the usual integer overflow.

In reply to Re^6: NaN output by Laurent_R
in thread NaN output by spikeinc

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