Several problems here:
- Array indexing starts at 0, not 1.
- In character classes (inside square brackets in a regex) you do not have to backslash brackets. ^ on the non-first position in a character class stands for itself.
- There are no capturing parentheses in the code, so $1 would be empty even if it worked.
- You have to evaluate the right hand side to turn the string $1 into the variable.
#!/usr/bin/perl
use warnings;
use strict;
sub replace {
s/$_[0]/$_[1]/eeg;
}
$_ = 'a { b } c ( d ) e';
my $nobrackets = qr/[^{}]+/;
replace(qr/\{($nobrackets)\}/, '$1');
print "$_\n";
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