Keep in mind that LIKE, to act as a substring search, needs to have % around the search value; either appended, or prepended, or on both sides (three different searches!); i.e.:

job LIKE 'trans01%' -- , or:

job LIKE '%trans01' -- , or:

job LIKE '%trans01%'

And job LIKE 'trans01' means: job equals 'trans01'. It is possible but unlikely because if you wanted equality you would normally spell it job = 'trans01'

If you use place holders: column like ( '%' || ? || '%' )

BTW, it seems you'd better forget about the ESCAPE '!' as they are not used in your statement anyway.

BTW 2: LIKE '%' doesn't do anything at all it seems so better to leave them out.

In reply to Re: Simplifying queries in DBI by erix
in thread Simplifying queries in DBI by neilwatson

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